-2s=3/4s+13

Solution for -2s=3/4s+13 equation:

-2s=3/4s+13

We move all terms to the left:

-2s-(3/4s+13)=0


Domain of the equation: 4s+13)!=0

s∈R


We get rid of parentheses

-2s-3/4s-13=0

We multiply all the terms by the denominator


-2s*4s-13*4s-3=0

Wy multiply elements

-8s^2-52s-3=0

a = -8; b = -52; c = -3;
Δ = b2-4ac
Δ = -522-4·(-8)·(-3)
Δ = 2608
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2608}=\sqrt{16*163}=\sqrt{16}*\sqrt{163}=4\sqrt{163}$
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-52)-4\sqrt{163}}{2*-8}=\frac{52-4\sqrt{163}}{-16}
$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-52)+4\sqrt{163}}{2*-8}=\frac{52+4\sqrt{163}}{-16}
$