-2sin(x)(2cos(x)+1)=0

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Solution for -2sin(x)(2cos(x)+1)=0 equation:


Simplifying
-2sin(x)(2cos(x) + 1) = 0

Multiply cos * x
-2ins * x(2cosx + 1) = 0

Reorder the terms:
-2ins * x(1 + 2cosx) = 0

Multiply ins * x
-2insx(1 + 2cosx) = 0
(1 * -2insx + 2cosx * -2insx) = 0

Reorder the terms:
(-4cinos2x2 + -2insx) = 0
(-4cinos2x2 + -2insx) = 0

Solving
-4cinos2x2 + -2insx = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '2insx' to each side of the equation.
-4cinos2x2 + -2insx + 2insx = 0 + 2insx

Combine like terms: -2insx + 2insx = 0
-4cinos2x2 + 0 = 0 + 2insx
-4cinos2x2 = 0 + 2insx
Remove the zero:
-4cinos2x2 = 2insx

Divide each side by '-4inos2x2'.
c = -0.5o-1s-1x-1

Simplifying
c = -0.5o-1s-1x-1

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