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-2t*t-16t+40=0
We add all the numbers together, and all the variables
-16t-2t*t+40=0
Wy multiply elements
-2t^2-16t+40=0
a = -2; b = -16; c = +40;
Δ = b2-4ac
Δ = -162-4·(-2)·40
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{576}=24$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-24}{2*-2}=\frac{-8}{-4} =+2 $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+24}{2*-2}=\frac{40}{-4} =-10 $
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