-2t+4(3t+2)=3(3t-3)+22

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Solution for -2t+4(3t+2)=3(3t-3)+22 equation:



-2t+4(3t+2)=3(3t-3)+22
We move all terms to the left:
-2t+4(3t+2)-(3(3t-3)+22)=0
We multiply parentheses
-2t+12t-(3(3t-3)+22)+8=0
We calculate terms in parentheses: -(3(3t-3)+22), so:
3(3t-3)+22
We multiply parentheses
9t-9+22
We add all the numbers together, and all the variables
9t+13
Back to the equation:
-(9t+13)
We add all the numbers together, and all the variables
10t-(9t+13)+8=0
We get rid of parentheses
10t-9t-13+8=0
We add all the numbers together, and all the variables
t-5=0
We move all terms containing t to the left, all other terms to the right
t=5

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