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-2u(-2u-4)=4u+11
We move all terms to the left:
-2u(-2u-4)-(4u+11)=0
We multiply parentheses
4u^2+8u-(4u+11)=0
We get rid of parentheses
4u^2+8u-4u-11=0
We add all the numbers together, and all the variables
4u^2+4u-11=0
a = 4; b = 4; c = -11;
Δ = b2-4ac
Δ = 42-4·4·(-11)
Δ = 192
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{192}=\sqrt{64*3}=\sqrt{64}*\sqrt{3}=8\sqrt{3}$$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-8\sqrt{3}}{2*4}=\frac{-4-8\sqrt{3}}{8} $$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+8\sqrt{3}}{2*4}=\frac{-4+8\sqrt{3}}{8} $
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