-2u(u+3)=3(u+4)+7

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Solution for -2u(u+3)=3(u+4)+7 equation:



-2u(u+3)=3(u+4)+7
We move all terms to the left:
-2u(u+3)-(3(u+4)+7)=0
We multiply parentheses
-2u^2-6u-(3(u+4)+7)=0
We calculate terms in parentheses: -(3(u+4)+7), so:
3(u+4)+7
We multiply parentheses
3u+12+7
We add all the numbers together, and all the variables
3u+19
Back to the equation:
-(3u+19)
We get rid of parentheses
-2u^2-6u-3u-19=0
We add all the numbers together, and all the variables
-2u^2-9u-19=0
a = -2; b = -9; c = -19;
Δ = b2-4ac
Δ = -92-4·(-2)·(-19)
Δ = -71
Delta is less than zero, so there is no solution for the equation

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