-2u+6(u+3)=2

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Solution for -2u+6(u+3)=2 equation:



-2u+6(u+3)=2
We move all terms to the left:
-2u+6(u+3)-(2)=0
We multiply parentheses
-2u+6u+18-2=0
We add all the numbers together, and all the variables
4u+16=0
We move all terms containing u to the left, all other terms to the right
4u=-16
u=-16/4
u=-4

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