-2u+6(u+3)=2

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Solution for -2u+6(u+3)=2 equation: 



-2u+6(u+3)=2

We move all terms to the left:

-2u+6(u+3)-(2)=0

We multiply parentheses

-2u+6u+18-2=0

We add all the numbers together, and all the variables

4u+16=0

We move all terms containing u to the left, all other terms to the right

4u=-16

u=-16/4

u=-4

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