-2v(v+1)=0v=

Solution for -2v(v+1)=0v= equation:

-2v(v+1)=0v=

We move all terms to the left:

-2v(v+1)-(0v)=0

We add all the numbers together, and all the variables

-1v-2v(v+1)=0

We multiply parentheses

-2v^2-1v-2v=0

We add all the numbers together, and all the variables

-2v^2-3v=0

a = -2; b = -3; c = 0;
Δ = b2-4ac
Δ = -32-4·(-2)·0
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-3}{2*-2}=\frac{0}{-4}
=0
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+3}{2*-2}=\frac{6}{-4}
=-1+1/2
$