-2w(w+2)=2w-4+4(2w+4)

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Solution for -2w(w+2)=2w-4+4(2w+4) equation:



-2w(w+2)=2w-4+4(2w+4)
We move all terms to the left:
-2w(w+2)-(2w-4+4(2w+4))=0
We multiply parentheses
-2w^2-4w-(2w-4+4(2w+4))=0
We calculate terms in parentheses: -(2w-4+4(2w+4)), so:
2w-4+4(2w+4)
determiningTheFunctionDomain 2w+4(2w+4)-4
We multiply parentheses
2w+8w+16-4
We add all the numbers together, and all the variables
10w+12
Back to the equation:
-(10w+12)
We get rid of parentheses
-2w^2-4w-10w-12=0
We add all the numbers together, and all the variables
-2w^2-14w-12=0
a = -2; b = -14; c = -12;
Δ = b2-4ac
Δ = -142-4·(-2)·(-12)
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-10}{2*-2}=\frac{4}{-4} =-1 $
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+10}{2*-2}=\frac{24}{-4} =-6 $

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