-2w(w+2)=2w-4+4(2w+4)

Solution for -2w(w+2)=2w-4+4(2w+4) equation:

-2w(w+2)=2w-4+4(2w+4)

We move all terms to the left:

-2w(w+2)-(2w-4+4(2w+4))=0

We multiply parentheses

-2w^2-4w-(2w-4+4(2w+4))=0


We calculate terms in parentheses: -(2w-4+4(2w+4)), so:

2w-4+4(2w+4)

determiningTheFunctionDomain
2w+4(2w+4)-4

We multiply parentheses

2w+8w+16-4

We add all the numbers together, and all the variables

10w+12

Back to the equation:

-(10w+12)


We get rid of parentheses

-2w^2-4w-10w-12=0

We add all the numbers together, and all the variables

-2w^2-14w-12=0

a = -2; b = -14; c = -12;
Δ = b2-4ac
Δ = -142-4·(-2)·(-12)
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-10}{2*-2}=\frac{4}{-4}
=-1
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+10}{2*-2}=\frac{24}{-4}
=-6
$