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-2x(-2x-7)=-2(x+1)
We move all terms to the left:
-2x(-2x-7)-(-2(x+1))=0
We multiply parentheses
4x^2+14x-(-2(x+1))=0
We calculate terms in parentheses: -(-2(x+1)), so:We get rid of parentheses
-2(x+1)
We multiply parentheses
-2x-2
Back to the equation:
-(-2x-2)
4x^2+14x+2x+2=0
We add all the numbers together, and all the variables
4x^2+16x+2=0
a = 4; b = 16; c = +2;
Δ = b2-4ac
Δ = 162-4·4·2
Δ = 224
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{224}=\sqrt{16*14}=\sqrt{16}*\sqrt{14}=4\sqrt{14}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-4\sqrt{14}}{2*4}=\frac{-16-4\sqrt{14}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+4\sqrt{14}}{2*4}=\frac{-16+4\sqrt{14}}{8} $
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