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-2x(-3x-1)-4x+3=25
We move all terms to the left:
-2x(-3x-1)-4x+3-(25)=0
We add all the numbers together, and all the variables
-4x-2x(-3x-1)-22=0
We multiply parentheses
6x^2-4x+2x-22=0
We add all the numbers together, and all the variables
6x^2-2x-22=0
a = 6; b = -2; c = -22;
Δ = b2-4ac
Δ = -22-4·6·(-22)
Δ = 532
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{532}=\sqrt{4*133}=\sqrt{4}*\sqrt{133}=2\sqrt{133}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2\sqrt{133}}{2*6}=\frac{2-2\sqrt{133}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2\sqrt{133}}{2*6}=\frac{2+2\sqrt{133}}{12} $
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