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-2x(-x-5)+5x+2=-9
We move all terms to the left:
-2x(-x-5)+5x+2-(-9)=0
We add all the numbers together, and all the variables
-2x(-1x-5)+5x+2-(-9)=0
We add all the numbers together, and all the variables
5x-2x(-1x-5)+11=0
We multiply parentheses
2x^2+5x+10x+11=0
We add all the numbers together, and all the variables
2x^2+15x+11=0
a = 2; b = 15; c = +11;
Δ = b2-4ac
Δ = 152-4·2·11
Δ = 137
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-\sqrt{137}}{2*2}=\frac{-15-\sqrt{137}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+\sqrt{137}}{2*2}=\frac{-15+\sqrt{137}}{4} $
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