-2x(2-15)=3x(46-5x)

Solution for -2x(2-15)=3x(46-5x) equation:

-2x(2-15)=3x(46-5x)

We move all terms to the left:

-2x(2-15)-(3x(46-5x))=0

We add all the numbers together, and all the variables

-2x(-13)-(3x(-5x+46))=0

We multiply parentheses

26x-(3x(-5x+46))=0


We calculate terms in parentheses: -(3x(-5x+46)), so:

3x(-5x+46)

We multiply parentheses

-15x^2+138x

Back to the equation:

-(-15x^2+138x)


We get rid of parentheses

15x^2-138x+26x=0

We add all the numbers together, and all the variables

15x^2-112x=0

a = 15; b = -112; c = 0;
Δ = b2-4ac
Δ = -1122-4·15·0
Δ = 12544
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{12544}=112$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-112)-112}{2*15}=\frac{0}{30}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-112)+112}{2*15}=\frac{224}{30}
=7+7/15
$