-2x(20-8x)-(15-5x)=(4x-5)(4x-5)

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Solution for -2x(20-8x)-(15-5x)=(4x-5)(4x-5) equation: 



-2x(20-8x)-(15-5x)=(4x-5)(4x-5)

We move all terms to the left:

-2x(20-8x)-(15-5x)-((4x-5)(4x-5))=0

We add all the numbers together, and all the variables

-2x(-8x+20)-(-5x+15)-((4x-5)(4x-5))=0

We multiply parentheses

16x^2-40x-(-5x+15)-((4x-5)(4x-5))=0

We get rid of parentheses

16x^2-40x+5x-((4x-5)(4x-5))-15=0

We multiply parentheses ..

16x^2-((+16x^2-20x-20x+25))-40x+5x-15=0



We calculate terms in parentheses: -((+16x^2-20x-20x+25)), so:

(+16x^2-20x-20x+25)

We get rid of parentheses

16x^2-20x-20x+25

We add all the numbers together, and all the variables

16x^2-40x+25

Back to the equation:

-(16x^2-40x+25)



We add all the numbers together, and all the variables

16x^2-35x-(16x^2-40x+25)-15=0

We get rid of parentheses

16x^2-16x^2-35x+40x-25-15=0

We add all the numbers together, and all the variables

5x-40=0

We move all terms containing x to the left, all other terms to the right

5x=40

x=40/5

x=8

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