-2x(2x-4)=-4(-x+2)

Solution for -2x(2x-4)=-4(-x+2) equation:

-2x(2x-4)=-4(-x+2)

We move all terms to the left:

-2x(2x-4)-(-4(-x+2))=0

We add all the numbers together, and all the variables

-2x(2x-4)-(-4(-1x+2))=0

We multiply parentheses

-4x^2+8x-(-4(-1x+2))=0


We calculate terms in parentheses: -(-4(-1x+2)), so:

-4(-1x+2)

We multiply parentheses

4x-8

Back to the equation:

-(4x-8)


We get rid of parentheses

-4x^2+8x-4x+8=0

We add all the numbers together, and all the variables

-4x^2+4x+8=0

a = -4; b = 4; c = +8;
Δ = b2-4ac
Δ = 42-4·(-4)·8
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-12}{2*-4}=\frac{-16}{-8}
=+2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+12}{2*-4}=\frac{8}{-8}
=-1
$