-2x(3x+4)+4(3x-4)=(5x-4)-3x

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Solution for -2x(3x+4)+4(3x-4)=(5x-4)-3x equation: 



-2x(3x+4)+4(3x-4)=(5x-4)-3x

We move all terms to the left:

-2x(3x+4)+4(3x-4)-((5x-4)-3x)=0

We multiply parentheses

-6x^2-8x+12x-((5x-4)-3x)-16=0



We calculate terms in parentheses: -((5x-4)-3x), so:

(5x-4)-3x

We add all the numbers together, and all the variables

-3x+(5x-4)

We get rid of parentheses

-3x+5x-4

We add all the numbers together, and all the variables

2x-4

Back to the equation:

-(2x-4)



We add all the numbers together, and all the variables

-6x^2+4x-(2x-4)-16=0

We get rid of parentheses

-6x^2+4x-2x+4-16=0

We add all the numbers together, and all the variables

-6x^2+2x-12=0

a = -6; b = 2; c = -12;
Δ = b2-4ac
Δ = 22-4·(-6)·(-12)
Δ = -284
Delta is less than zero, so there is no solution for the equation

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