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-2x(3x+4)/5=-7+3x
We move all terms to the left:
-2x(3x+4)/5-(-7+3x)=0
We add all the numbers together, and all the variables
-2x(3x+4)/5-(3x-7)=0
We get rid of parentheses
-2x(3x+4)/5-3x+7=0
We multiply all the terms by the denominator
-2x(3x+4)-3x*5+7*5=0
We add all the numbers together, and all the variables
-2x(3x+4)-3x*5+35=0
We multiply parentheses
-6x^2-8x-3x*5+35=0
Wy multiply elements
-6x^2-8x-15x+35=0
We add all the numbers together, and all the variables
-6x^2-23x+35=0
a = -6; b = -23; c = +35;
Δ = b2-4ac
Δ = -232-4·(-6)·35
Δ = 1369
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1369}=37$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-23)-37}{2*-6}=\frac{-14}{-12} =1+1/6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-23)+37}{2*-6}=\frac{60}{-12} =-5 $
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