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-2x(3x+7)=-63+7x
We move all terms to the left:
-2x(3x+7)-(-63+7x)=0
We add all the numbers together, and all the variables
-2x(3x+7)-(7x-63)=0
We multiply parentheses
-6x^2-14x-(7x-63)=0
We get rid of parentheses
-6x^2-14x-7x+63=0
We add all the numbers together, and all the variables
-6x^2-21x+63=0
a = -6; b = -21; c = +63;
Δ = b2-4ac
Δ = -212-4·(-6)·63
Δ = 1953
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1953}=\sqrt{9*217}=\sqrt{9}*\sqrt{217}=3\sqrt{217}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-21)-3\sqrt{217}}{2*-6}=\frac{21-3\sqrt{217}}{-12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-21)+3\sqrt{217}}{2*-6}=\frac{21+3\sqrt{217}}{-12} $
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