-2x(3x-5)=4(x+3)+8

Solution for -2x(3x-5)=4(x+3)+8 equation:

-2x(3x-5)=4(x+3)+8

We move all terms to the left:

-2x(3x-5)-(4(x+3)+8)=0

We multiply parentheses

-6x^2+10x-(4(x+3)+8)=0


We calculate terms in parentheses: -(4(x+3)+8), so:

4(x+3)+8

We multiply parentheses

4x+12+8

We add all the numbers together, and all the variables

4x+20

Back to the equation:

-(4x+20)


We get rid of parentheses

-6x^2+10x-4x-20=0

We add all the numbers together, and all the variables

-6x^2+6x-20=0

a = -6; b = 6; c = -20;
Δ = b2-4ac
Δ = 62-4·(-6)·(-20)
Δ = -444
Delta is less than zero, so there is no solution for the equation