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-2x(5x-3)=5x
We move all terms to the left:
-2x(5x-3)-(5x)=0
We add all the numbers together, and all the variables
-5x-2x(5x-3)=0
We multiply parentheses
-10x^2-5x+6x=0
We add all the numbers together, and all the variables
-10x^2+x=0
a = -10; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·(-10)·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*-10}=\frac{-2}{-20} =1/10 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*-10}=\frac{0}{-20} =0 $
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