-2x(x-12)+10=4

Solution for -2x(x-12)+10=4 equation:

-2x(x-12)+10=4

We move all terms to the left:

-2x(x-12)+10-(4)=0

We add all the numbers together, and all the variables

-2x(x-12)+6=0

We multiply parentheses

-2x^2+24x+6=0

a = -2; b = 24; c = +6;
Δ = b2-4ac
Δ = 242-4·(-2)·6
Δ = 624
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{624}=\sqrt{16*39}=\sqrt{16}*\sqrt{39}=4\sqrt{39}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-4\sqrt{39}}{2*-2}=\frac{-24-4\sqrt{39}}{-4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+4\sqrt{39}}{2*-2}=\frac{-24+4\sqrt{39}}{-4}
$