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-2x(x-2)=-3-2x
We move all terms to the left:
-2x(x-2)-(-3-2x)=0
We add all the numbers together, and all the variables
-2x(x-2)-(-2x-3)=0
We multiply parentheses
-2x^2+4x-(-2x-3)=0
We get rid of parentheses
-2x^2+4x+2x+3=0
We add all the numbers together, and all the variables
-2x^2+6x+3=0
a = -2; b = 6; c = +3;
Δ = b2-4ac
Δ = 62-4·(-2)·3
Δ = 60
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{60}=\sqrt{4*15}=\sqrt{4}*\sqrt{15}=2\sqrt{15}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-2\sqrt{15}}{2*-2}=\frac{-6-2\sqrt{15}}{-4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+2\sqrt{15}}{2*-2}=\frac{-6+2\sqrt{15}}{-4} $
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