-2x(x-3)=-4

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Solution for -2x(x-3)=-4 equation:



-2x(x-3)=-4
We move all terms to the left:
-2x(x-3)-(-4)=0
We add all the numbers together, and all the variables
-2x(x-3)+4=0
We multiply parentheses
-2x^2+6x+4=0
a = -2; b = 6; c = +4;
Δ = b2-4ac
Δ = 62-4·(-2)·4
Δ = 68
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{68}=\sqrt{4*17}=\sqrt{4}*\sqrt{17}=2\sqrt{17}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-2\sqrt{17}}{2*-2}=\frac{-6-2\sqrt{17}}{-4} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+2\sqrt{17}}{2*-2}=\frac{-6+2\sqrt{17}}{-4} $

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