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-2x(x-3)=2x-6
We move all terms to the left:
-2x(x-3)-(2x-6)=0
We multiply parentheses
-2x^2+6x-(2x-6)=0
We get rid of parentheses
-2x^2+6x-2x+6=0
We add all the numbers together, and all the variables
-2x^2+4x+6=0
a = -2; b = 4; c = +6;
Δ = b2-4ac
Δ = 42-4·(-2)·6
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{64}=8$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-8}{2*-2}=\frac{-12}{-4} =+3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+8}{2*-2}=\frac{4}{-4} =-1 $
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