-2x(x-5)-62=7x-9(x-2)

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Solution for -2x(x-5)-62=7x-9(x-2) equation: 



-2x(x-5)-62=7x-9(x-2)

We move all terms to the left:

-2x(x-5)-62-(7x-9(x-2))=0

We multiply parentheses

-2x^2+10x-(7x-9(x-2))-62=0



We calculate terms in parentheses: -(7x-9(x-2)), so:

7x-9(x-2)

We multiply parentheses

7x-9x+18

We add all the numbers together, and all the variables

-2x+18

Back to the equation:

-(-2x+18)



We get rid of parentheses

-2x^2+10x+2x-18-62=0

We add all the numbers together, and all the variables

-2x^2+12x-80=0

a = -2; b = 12; c = -80;
Δ = b2-4ac
Δ = 122-4·(-2)·(-80)
Δ = -496
Delta is less than zero, so there is no solution for the equation

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