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-2x(x-5)=-14
We move all terms to the left:
-2x(x-5)-(-14)=0
We add all the numbers together, and all the variables
-2x(x-5)+14=0
We multiply parentheses
-2x^2+10x+14=0
a = -2; b = 10; c = +14;
Δ = b2-4ac
Δ = 102-4·(-2)·14
Δ = 212
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{212}=\sqrt{4*53}=\sqrt{4}*\sqrt{53}=2\sqrt{53}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-2\sqrt{53}}{2*-2}=\frac{-10-2\sqrt{53}}{-4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+2\sqrt{53}}{2*-2}=\frac{-10+2\sqrt{53}}{-4} $
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