-2x+(1/2x-1)=2

Solution for -2x+(1/2x-1)=2 equation:

-2x+(1/2x-1)=2

We move all terms to the left:

-2x+(1/2x-1)-(2)=0


Domain of the equation: 2x-1)!=0

x∈R


We get rid of parentheses

-2x+1/2x-1-2=0

We multiply all the terms by the denominator


-2x*2x-1*2x-2*2x+1=0

Wy multiply elements

-4x^2-2x-4x+1=0

We add all the numbers together, and all the variables

-4x^2-6x+1=0

a = -4; b = -6; c = +1;
Δ = b2-4ac
Δ = -62-4·(-4)·1
Δ = 52
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{52}=\sqrt{4*13}=\sqrt{4}*\sqrt{13}=2\sqrt{13}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-2\sqrt{13}}{2*-4}=\frac{6-2\sqrt{13}}{-8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+2\sqrt{13}}{2*-4}=\frac{6+2\sqrt{13}}{-8}
$