-2x+(1/x)=-2

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Solution for -2x+(1/x)=-2 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

1/x-2*x = -2 // + 2

1/x-2*x+2 = 0

1*x^-1-2*x^1+2*x^0 = 0

(2*x^1-2*x^2+1*x^0)/(x^1) = 0 // * x^2

x^1*(2*x^1-2*x^2+1*x^0) = 0

x^1

2*x-2*x^2+1 = 0

2*x-2*x^2+1 = 0

DELTA = 2^2-(-2*1*4)

DELTA = 12

DELTA > 0

x = (12^(1/2)-2)/(-2*2) or x = (-12^(1/2)-2)/(-2*2)

x = (2*3^(1/2)-2)/(-4) or x = (-2*3^(1/2)-2)/(-4)

x in { (2*3^(1/2)-2)/(-4), (-2*3^(1/2)-2)/(-4)} 

x in { (2*3^(1/2)-2)/(-4), (-2*3^(1/2)-2)/(-4) }

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