-2x+1-(3+-3x)=-4+(-x)-2

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Solution for -2x+1-(3+-3x)=-4+(-x)-2 equation: 



-2x+1-(3+-3x)=-4+(-x)-2

We move all terms to the left:

-2x+1-(3+-3x)-(-4+(-x)-2)=0

We add all the numbers together, and all the variables

-2x-(-3x)-(-4+(-1x)-2)+1=0

We get rid of parentheses

-2x+3x-(-4+(-1x)-2)+1=0



We calculate terms in parentheses: -(-4+(-1x)-2), so:

-4+(-1x)-2

determiningTheFunctionDomain
(-1x)-4-2

We add all the numbers together, and all the variables

(-1x)-6

We get rid of parentheses

-1x-6

Back to the equation:

-(-1x-6)



We add all the numbers together, and all the variables

x-(-1x-6)+1=0

We get rid of parentheses

x+1x+6+1=0

We add all the numbers together, and all the variables

2x+7=0

We move all terms containing x to the left, all other terms to the right

2x=-7

x=-7/2

x=-3+1/2

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