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-2x+2+4+4x+4=2(x+3)
We move all terms to the left:
-2x+2+4+4x+4-(2(x+3))=0
We add all the numbers together, and all the variables
2x-(2(x+3))+10=0
We calculate terms in parentheses: -(2(x+3)), so:We get rid of parentheses
2(x+3)
We multiply parentheses
2x+6
Back to the equation:
-(2x+6)
2x-2x-6+10=0
We add all the numbers together, and all the variables
4!=0
There is no solution for this equation
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