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-2x+2=-3/4x-3
We move all terms to the left:
-2x+2-(-3/4x-3)=0
Domain of the equation: 4x-3)!=0We get rid of parentheses
x∈R
-2x+3/4x+3+2=0
We multiply all the terms by the denominator
-2x*4x+3*4x+2*4x+3=0
Wy multiply elements
-8x^2+12x+8x+3=0
We add all the numbers together, and all the variables
-8x^2+20x+3=0
a = -8; b = 20; c = +3;
Δ = b2-4ac
Δ = 202-4·(-8)·3
Δ = 496
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{496}=\sqrt{16*31}=\sqrt{16}*\sqrt{31}=4\sqrt{31}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-4\sqrt{31}}{2*-8}=\frac{-20-4\sqrt{31}}{-16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+4\sqrt{31}}{2*-8}=\frac{-20+4\sqrt{31}}{-16} $
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