-2x+4=2(4x-3)(-8+4x)

Solution for -2x+4=2(4x-3)(-8+4x) equation:

-2x+4=2(4x-3)(-8+4x)

We move all terms to the left:

-2x+4-(2(4x-3)(-8+4x))=0

We add all the numbers together, and all the variables

-2x-(2(4x-3)(4x-8))+4=0

We multiply parentheses ..

-(2(+16x^2-32x-12x+24))-2x+4=0


We calculate terms in parentheses: -(2(+16x^2-32x-12x+24)), so:

2(+16x^2-32x-12x+24)

We multiply parentheses

32x^2-64x-24x+48

We add all the numbers together, and all the variables

32x^2-88x+48

Back to the equation:

-(32x^2-88x+48)


We add all the numbers together, and all the variables

-2x-(32x^2-88x+48)+4=0

We get rid of parentheses

-32x^2-2x+88x-48+4=0

We add all the numbers together, and all the variables

-32x^2+86x-44=0

a = -32; b = 86; c = -44;
Δ = b2-4ac
Δ = 862-4·(-32)·(-44)
Δ = 1764
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1764}=42$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(86)-42}{2*-32}=\frac{-128}{-64}
=+2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(86)+42}{2*-32}=\frac{-44}{-64}
=11/16
$