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-2x+4x-6=2(x-2)-4
We move all terms to the left:
-2x+4x-6-(2(x-2)-4)=0
We add all the numbers together, and all the variables
2x-(2(x-2)-4)-6=0
We calculate terms in parentheses: -(2(x-2)-4), so:We get rid of parentheses
2(x-2)-4
We multiply parentheses
2x-4-4
We add all the numbers together, and all the variables
2x-8
Back to the equation:
-(2x-8)
2x-2x+8-6=0
We add all the numbers together, and all the variables
2!=0
There is no solution for this equation
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