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-2x+5/2x=17
We move all terms to the left:
-2x+5/2x-(17)=0
Domain of the equation: 2x!=0We multiply all the terms by the denominator
x!=0/2
x!=0
x∈R
-2x*2x-17*2x+5=0
Wy multiply elements
-4x^2-34x+5=0
a = -4; b = -34; c = +5;
Δ = b2-4ac
Δ = -342-4·(-4)·5
Δ = 1236
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1236}=\sqrt{4*309}=\sqrt{4}*\sqrt{309}=2\sqrt{309}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-34)-2\sqrt{309}}{2*-4}=\frac{34-2\sqrt{309}}{-8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-34)+2\sqrt{309}}{2*-4}=\frac{34+2\sqrt{309}}{-8} $
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