-2x+x=4(x-5)-2(1-3x)

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Solution for -2x+x=4(x-5)-2(1-3x) equation: 



-2x+x=4(x-5)-2(1-3x)

We move all terms to the left:

-2x+x-(4(x-5)-2(1-3x))=0

We add all the numbers together, and all the variables

-2x+x-(4(x-5)-2(-3x+1))=0

We add all the numbers together, and all the variables

-1x-(4(x-5)-2(-3x+1))=0



We calculate terms in parentheses: -(4(x-5)-2(-3x+1)), so:

4(x-5)-2(-3x+1)

We multiply parentheses

4x+6x-20-2

We add all the numbers together, and all the variables

10x-22

Back to the equation:

-(10x-22)



We get rid of parentheses

-1x-10x+22=0

We add all the numbers together, and all the variables

-11x+22=0

We move all terms containing x to the left, all other terms to the right

-11x=-22

x=-22/-11

x=+2

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