-2x-14=4(x+4)x=

Solution for -2x-14=4(x+4)x= equation:

-2x-14=4(x+4)x=

We move all terms to the left:

-2x-14-(4(x+4)x)=0


We calculate terms in parentheses: -(4(x+4)x), so:

4(x+4)x

We multiply parentheses

4x^2+16x

Back to the equation:

-(4x^2+16x)


We get rid of parentheses

-4x^2-2x-16x-14=0

We add all the numbers together, and all the variables

-4x^2-18x-14=0

a = -4; b = -18; c = -14;
Δ = b2-4ac
Δ = -182-4·(-4)·(-14)
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-10}{2*-4}=\frac{8}{-8}
=-1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+10}{2*-4}=\frac{28}{-8}
=-3+1/2
$