-2x-2(2x-3)=3(x+2)

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Solution for -2x-2(2x-3)=3(x+2) equation:



-2x-2(2x-3)=3(x+2)
We move all terms to the left:
-2x-2(2x-3)-(3(x+2))=0
We multiply parentheses
-2x-4x-(3(x+2))+6=0
We calculate terms in parentheses: -(3(x+2)), so:
3(x+2)
We multiply parentheses
3x+6
Back to the equation:
-(3x+6)
We add all the numbers together, and all the variables
-6x-(3x+6)+6=0
We get rid of parentheses
-6x-3x-6+6=0
We add all the numbers together, and all the variables
-9x=0
x=0/-9
x=0

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