-2x-39=3(-6x-7)7x

Solution for -2x-39=3(-6x-7)7x equation:

-2x-39=3(-6x-7)7x

We move all terms to the left:

-2x-39-(3(-6x-7)7x)=0


We calculate terms in parentheses: -(3(-6x-7)7x), so:

3(-6x-7)7x

We multiply parentheses

-126x^2-147x

Back to the equation:

-(-126x^2-147x)


We get rid of parentheses

126x^2+147x-2x-39=0

We add all the numbers together, and all the variables

126x^2+145x-39=0

a = 126; b = 145; c = -39;
Δ = b2-4ac
Δ = 1452-4·126·(-39)
Δ = 40681
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(145)-\sqrt{40681}}{2*126}=\frac{-145-\sqrt{40681}}{252}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(145)+\sqrt{40681}}{2*126}=\frac{-145+\sqrt{40681}}{252}
$