-2x-4(2-3x)=4(x-5)-12

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Solution for -2x-4(2-3x)=4(x-5)-12 equation: 



-2x-4(2-3x)=4(x-5)-12

We move all terms to the left:

-2x-4(2-3x)-(4(x-5)-12)=0

We add all the numbers together, and all the variables

-2x-4(-3x+2)-(4(x-5)-12)=0

We multiply parentheses

-2x+12x-(4(x-5)-12)-8=0



We calculate terms in parentheses: -(4(x-5)-12), so:

4(x-5)-12

We multiply parentheses

4x-20-12

We add all the numbers together, and all the variables

4x-32

Back to the equation:

-(4x-32)



We add all the numbers together, and all the variables

10x-(4x-32)-8=0

We get rid of parentheses

10x-4x+32-8=0

We add all the numbers together, and all the variables

6x+24=0

We move all terms containing x to the left, all other terms to the right

6x=-24

x=-24/6

x=-4

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