-2x-9+3x+4=+x2+4x-7

Solution for -2x-9+3x+4=+x2+4x-7 equation:

-2x-9+3x+4=+x2+4x-7

We move all terms to the left:

-2x-9+3x+4-(+x2+4x-7)=0

We add all the numbers together, and all the variables

-(+x^2+4x-7)-2x+3x-9+4=0

We add all the numbers together, and all the variables

-(+x^2+4x-7)+x-5=0

We get rid of parentheses

-x^2-4x+x+7-5=0

We add all the numbers together, and all the variables

-1x^2-3x+2=0

a = -1; b = -3; c = +2;
Δ = b2-4ac
Δ = -32-4·(-1)·2
Δ = 17
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{17}}{2*-1}=\frac{3-\sqrt{17}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{17}}{2*-1}=\frac{3+\sqrt{17}}{-2}
$