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-2x^2+16x-32=0
a = -2; b = 16; c = -32;
Δ = b2-4ac
Δ = 162-4·(-2)·(-32)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{-16}{-4}=+4$
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