-2x2+16x-32=0

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Solution for -2x2+16x-32=0 equation: 



-2x^2+16x-32=0

a = -2; b = 16; c = -32;
Δ = b2-4ac
Δ = 162-4·(-2)·(-32)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-16}{-4}=+4$

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