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-2x^2+18x-36=0
a = -2; b = 18; c = -36;
Δ = b2-4ac
Δ = 182-4·(-2)·(-36)
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36}=6$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-6}{2*-2}=\frac{-24}{-4} =+6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+6}{2*-2}=\frac{-12}{-4} =+3 $
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