-2x2+27x-85=-4x2+51x-149

Solution for -2x2+27x-85=-4x2+51x-149 equation:

-2x^2+27x-85=-4x^2+51x-149

We move all terms to the left:

-2x^2+27x-85-(-4x^2+51x-149)=0

We get rid of parentheses

-2x^2+4x^2-51x+27x+149-85=0

We add all the numbers together, and all the variables

2x^2-24x+64=0

a = 2; b = -24; c = +64;
Δ = b2-4ac
Δ = -242-4·2·64
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-8}{2*2}=\frac{16}{4}
=4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+8}{2*2}=\frac{32}{4}
=8
$