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-2x^2+30x=100
We move all terms to the left:
-2x^2+30x-(100)=0
a = -2; b = 30; c = -100;
Δ = b2-4ac
Δ = 302-4·(-2)·(-100)
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{100}=10$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-10}{2*-2}=\frac{-40}{-4} =+10 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+10}{2*-2}=\frac{-20}{-4} =+5 $
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