-2x2+4x=12x+40

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Solution for -2x2+4x=12x+40 equation: 



-2x^2+4x=12x+40

We move all terms to the left:

-2x^2+4x-(12x+40)=0

We get rid of parentheses

-2x^2+4x-12x-40=0

We add all the numbers together, and all the variables

-2x^2-8x-40=0

a = -2; b = -8; c = -40;
Δ = b2-4ac
Δ = -82-4·(-2)·(-40)
Δ = -256
Delta is less than zero, so there is no solution for the equation

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