-2x2-10x+252=0

Solution for -2x2-10x+252=0 equation:

-2x^2-10x+252=0

a = -2; b = -10; c = +252;
Δ = b2-4ac
Δ = -102-4·(-2)·252
Δ = 2116
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2116}=46$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-46}{2*-2}=\frac{-36}{-4}
=+9
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+46}{2*-2}=\frac{56}{-4}
=-14
$