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-2x^2-36x-160=-4x^2-66x-272
We move all terms to the left:
-2x^2-36x-160-(-4x^2-66x-272)=0
We get rid of parentheses
-2x^2+4x^2+66x-36x+272-160=0
We add all the numbers together, and all the variables
2x^2+30x+112=0
a = 2; b = 30; c = +112;
Δ = b2-4ac
Δ = 302-4·2·112
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4}=2$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-2}{2*2}=\frac{-32}{4} =-8 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+2}{2*2}=\frac{-28}{4} =-7 $
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