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-2x^2=-15
We move all terms to the left:
-2x^2-(-15)=0
We add all the numbers together, and all the variables
-2x^2+15=0
a = -2; b = 0; c = +15;
Δ = b2-4ac
Δ = 02-4·(-2)·15
Δ = 120
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{120}=\sqrt{4*30}=\sqrt{4}*\sqrt{30}=2\sqrt{30}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{30}}{2*-2}=\frac{0-2\sqrt{30}}{-4} =-\frac{2\sqrt{30}}{-4} =-\frac{\sqrt{30}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{30}}{2*-2}=\frac{0+2\sqrt{30}}{-4} =\frac{2\sqrt{30}}{-4} =\frac{\sqrt{30}}{-2} $
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