-2x2=-216

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Solution for -2x2=-216 equation:



-2x^2=-216
We move all terms to the left:
-2x^2-(-216)=0
We add all the numbers together, and all the variables
-2x^2+216=0
a = -2; b = 0; c = +216;
Δ = b2-4ac
Δ = 02-4·(-2)·216
Δ = 1728
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{1728}=\sqrt{576*3}=\sqrt{576}*\sqrt{3}=24\sqrt{3}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-24\sqrt{3}}{2*-2}=\frac{0-24\sqrt{3}}{-4} =-\frac{24\sqrt{3}}{-4} =-\frac{6\sqrt{3}}{-1} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+24\sqrt{3}}{2*-2}=\frac{0+24\sqrt{3}}{-4} =\frac{24\sqrt{3}}{-4} =\frac{6\sqrt{3}}{-1} $

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