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-2x=3/4x-5
We move all terms to the left:
-2x-(3/4x-5)=0
Domain of the equation: 4x-5)!=0We get rid of parentheses
x∈R
-2x-3/4x+5=0
We multiply all the terms by the denominator
-2x*4x+5*4x-3=0
Wy multiply elements
-8x^2+20x-3=0
a = -8; b = 20; c = -3;
Δ = b2-4ac
Δ = 202-4·(-8)·(-3)
Δ = 304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{304}=\sqrt{16*19}=\sqrt{16}*\sqrt{19}=4\sqrt{19}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-4\sqrt{19}}{2*-8}=\frac{-20-4\sqrt{19}}{-16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+4\sqrt{19}}{2*-8}=\frac{-20+4\sqrt{19}}{-16} $
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